900=5w^2

Solution for 900=5w^2 equation:

900=5w^2

We move all terms to the left:

900-(5w^2)=0

a = -5; b = 0; c = +900;
Δ = b2-4ac
Δ = 02-4·(-5)·900
Δ = 18000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18000}=\sqrt{3600*5}=\sqrt{3600}*\sqrt{5}=60\sqrt{5}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{5}}{2*-5}=\frac{0-60\sqrt{5}}{-10}
=-\frac{60\sqrt{5}}{-10}
=-\frac{6\sqrt{5}}{-1}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{5}}{2*-5}=\frac{0+60\sqrt{5}}{-10}
=\frac{60\sqrt{5}}{-10}
=\frac{6\sqrt{5}}{-1}
$